Ten Sleep is a town located in Washakie County, Wyoming. Ten Sleep has a 2025 population of 263. Ten Sleep is currently growing at a rate of 1.15% annually and its population has increased by 6.48% since the most recent census, which recorded a population of 247 in 2020.
The average household income in Ten Sleep is $46,003 with a poverty rate of 37.38%.The median age in Ten Sleep is 54.5 years: 23.6 years for males, and 61.9 years for females.
Data after 2023 is projected based on recent change
The racial composition of Ten Sleep includes 88.79% White, and smaller percentages for Asian and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 190 | 88.79% |
Two or more races | 22 | 10.28% |
Asian | 2 | 0.93% |
Married
Widowed
Divorced
Separated
Never Married
Ten Sleep's average per capita income is $21,250. Household income levels show a median of $30,893. The poverty rate stands at 37.38%.
Name | Median | Mean |
---|---|---|
Married Families | $108,438 | - |
Households | $30,893 | $46,003 |
Non Families | $24,667 | $34,868 |
Families | - | $61,002 |
Average Income
Median Household Income
Poverty Rate